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Updated weekly

The Weekly Puzzle

One mathematical puzzle, every Tuesday. Send in your solution by email, drop by a meeting, or just enjoy it on your own. Past puzzles and solutions are below.

This week

Week 1StandardReleased Tue, Sep 8, 2026 · Solutions due Mon, Sep 14, 2026

Crossing five

Find the smallest positive integer n such that 1 + 1/2 + 1/3 + … + 1/n exceeds 5. Closed-form arguments welcome; clever bounds even more so.

Show a hint

The harmonic numbers grow like ln(n) + γ. Use this to estimate n, then check carefully around your estimate.

Email a solutionOr bring it to the next meeting. Both count.

How it works

A new puzzle appears here each Tuesday. They're chosen to be approachable with pen and paper, no special background required. Try the hint first; the solution gets posted with the next week's puzzle.

How to submit

Email us your solution before the deadline, or bring it to the next meeting. We love elegant solutions, but partial credit is real, and so is "here's where I got stuck."

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Archive

Past puzzles & solutions

Tap a card to reveal the hint or the full solution. Solvers are listed with permission.

  • Week 0Warm-upReleased Tue, Sep 1, 2026 · Solutions due Mon, Sep 7, 2026

    Tiling a 2 × 10 board

    In how many ways can you tile a 2 × 10 board using 1 × 2 dominoes (placed either horizontally or vertically)?

    Show a hint

    Let T(n) be the number of tilings of a 2 × n board. Find a recurrence by considering the leftmost piece.

    Show the solution

    T(n) satisfies T(n) = T(n − 1) + T(n − 2) with T(1) = 1, T(2) = 2, which gives the Fibonacci sequence shifted by one. So T(10) = F(11) = 89.

    Solvers: Anna L., Marcus W., Priya S.

  • Week -1StandardReleased Tue, Aug 25, 2026 · Solutions due Mon, Aug 31, 2026

    Divisibility detour

    Find all positive integers n such that n + 1 divides n² + 1.

    Show a hint

    Polynomial long division. What is n² + 1 modulo n + 1?

    Show the solution

    Since n² + 1 = (n + 1)(n − 1) + 2, we have (n² + 1) mod (n + 1) = 2. So (n + 1) | (n² + 1) iff (n + 1) | 2, which gives n + 1 ∈ {1, 2}, hence n = 1.

    Solvers: Devi T., Jonas K.